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![[Post New]](/templates/default/images/icon_minipost_new.gif) 22 Nov 2007 18:08:51 IST
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in answering a question on a multiple choice test a person either knows the answer or guesses.let 3/4 be the probability that he knows the answer and 1/4 be the probability that he guesses.assuming that a a student who guesses will be correct with probability 1/4 what is the probability that the student knows the answer , given that he has answered it correctly? conditions : u are not allowed to use bayes' theorem u are allowed to use only the basic probability formula P=no. of favourable outcomes/sample space
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science-
the most fundamental
the most eternal
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22 Nov 2007 19:27:02 IST
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come on goiitians take a go at this .its a good one ,trust me.
person who answers this before 6pm tomorrow gets two hats
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science-
the most fundamental
the most eternal
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22 Nov 2007 20:43:58 IST
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Buddy you can use fav.outcomes/tot. outcomes only when each event is equally likely to occur,right?Here I dont think thats the case..
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22 Nov 2007 20:52:46 IST
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is the answer 3/4 + 1/16 =13/16 ????
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The only place where you will find success before hard work is in the dictionary
A winner never quits.....a quitter never wins......
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22 Nov 2007 20:57:56 IST
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plz reply,,,,,,,,,,,,,,,,,,,,
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The only place where you will find success before hard work is in the dictionary
A winner never quits.....a quitter never wins......
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22 Nov 2007 20:58:12 IST
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@learner
yep u can -just think
@ananth
nope that isnt the answer
anyway how did u work that out
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