IIT JEE , AIEEE Forum - Mathematics , Algebra - The equationx.x+ax-a.a-1=0will have roots of opposite signs if ..................

nickyyyyyyyyyyy

The equationx.x+ax-a.a-1=0will have roots of opposite signs if ..................

hamba

Assuming ur equation to be of the form $\ x^2+ax-a^2-1=0$ , We have that the product to be negative :-

$\ -a^2-1<0\implies\ a^2+1>0$ - WHICH IS OBVIOUS AND THE REQD CONDITION......TO BE MORE PRECISE - 'a' HAS TO BE REAL.

hamba

Or, a²>-1, a>i

Decoder

wat is this a> i... ???

is this a serious statement ???

hamba

Seriously I'm not finding any reason why u can't understand it, seeing u r a 12th std guy?????

Decoder

a>i..i haven't seen this in my whole studies yaar...

hamba

Then in short take this a²>-1? Is it now okay?

hamba

To avoid these complexities, I had mentioned a has to be real, that's simple isn't it?

Decoder

yes..tht's for all values...

there is no need to put an inequality sign with a complex quantity alongside it... :):) ..

u can never compare the greatness of two complex quantities..tht's why a>i..turned my head..

hamba

AGAIN AN IDIOTIC COMMENT FROM MY SIDE......SORRY AGAIN......I FORGOT INEQUALITY DOESN'T HOLD IN THE COMPLEX DOMAIN.

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