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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 Jul 2008 20:01:07 IST
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the max. value of |z| where z satisfiies the condition |z+2/z|=2 is
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 Jul 2008 20:05:24 IST
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take z= r exp ( i@)
Now put this value in the given qty and then u will find a quadratic eqn in r . ( with @ as a parameter)
Solve for r and see for what value of @ r gets max .
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 Jul 2008 20:10:23 IST
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u cud do it usng dis way also.....put z= R (cos@ + i sin@)
u have the reqd. expression as / R (cos @ + isin@ ) + (1/R)(cos @ - isin@ ) / = 2 ...u cud dus proceed and solve for max value of R....
rate if useful...
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"Logic is the systematic way of reaching the wrong conclusion with confidence" lol..... |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 Jul 2008 20:23:54 IST
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Time wounds all heels |
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