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![[Post New]](/templates/default/images/icon_minipost_new.gif) 5 Apr 2008 11:22:53 IST
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2^(x/2)+( 2+1)^x=(5+2 2)^(x/2)
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 5 Apr 2008 11:31:26 IST
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x=0 nd x=2 are the two solutions
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 5 Apr 2008 11:49:59 IST
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nice GUESS, but unfortunately its wrong. LOL
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 5 Apr 2008 12:08:35 IST
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sorry x=0 is not the solution only x =2
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 5 Apr 2008 13:09:31 IST
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EDIT: there was an error in the previous answer . Now i think it is right. sorry for the mistake.

=> ![(\sqrt2)^x + (\sqrt{2} + 1)^x =[(\sqrt2)^2+(\sqrt{2} + 1)^2]^{\frac{x}{2}}](http://alt2.artofproblemsolving.com/Forum/latexrender/pictures/d/9/3/d934950792dfdbaea87348f5effb1ef2c32f5fbd.gif)
Obviously , x=2 is a solution.
Now, this is of the form, 
It can be proved that this does not have any other solution by using inequalities.
So x=2 is the only solution.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 5 Apr 2008 14:52:34 IST
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it is true that there is only one solution , but x=2 is the solution(not x=1), but i dont know how to solve this.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 5 Apr 2008 15:30:12 IST
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Check the answer now . sorry for the earlier wrong answer.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 5 Apr 2008 16:39:33 IST
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thnx
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