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Ask iit jee aieee pet cbse icse state board experts Expert Question: the number of positive integral solutions of the equation a*b*c*d*e=1050 are .....
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digs2digi (162)

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the number of positive integral solutions of the equation a*b*c*d*e=1050 are .....
    
digs2digi (162)

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plz help experts
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sagarvaze (253)

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is 1 a valid root ?
if it is not then you can have only 1 solution






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digs2digi (162)

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okay i will give the options
a)1870
b)1875
c)1865
d)1880
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digs2digi (162)

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yaar i found this ques in viteee sample questions with the options as i have given
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ziauddin75 (307)

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answer is b
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digs2digi (162)

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ya but tell me how???????????
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digs2digi (162)

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how????????????
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digs2digi (162)

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hello?????????/so gaye!!!!!!!!!!!
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sboosy (3011)

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a*b*c*d*e = 1050 = 2*3*5*5*7 \\ \\ \mbox{Now note carefully.2,3,7 can go to either one of} \ a,b,c,d,e \ \mbox{at the same time} \\ \\ \mbox{Thus we have} \ 5*5*5 \ \mbox{for each one of} \ 2,3,7 \\ \\ \mbox{Now} \ 5,5 \ \mbox{can go to each one of} \ a,b,c,d,e \ \mbox{as} \ 5 \ \mbox{or} \ 5^2 \\ \\ \mbox{Thus we have} \ 5*5*5*(5C_1+5C_2) = 125*15 = 1875
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shubham.123 (302)

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could u please explain ( sboosy) how it is 5 or 5^2???
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sboosy (3011)

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see we have 2*3*5*5*7 ...now what i m saying is that ..
first number could be (2*3*5*7)*5*1*1*1 or the other 5 could also go in ..since 5 is a repeat ..we have to consider combinations
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