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![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 Apr 2008 19:53:52 IST
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the number of positive integral solutions of the equation a*b*c*d*e=1050 are .....
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 Apr 2008 20:02:53 IST
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plz help experts
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 Apr 2008 20:09:58 IST
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is 1 a valid root ? if it is not then you can have only 1 solution
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 Apr 2008 20:10:02 IST
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okay i will give the options a)1870 b)1875 c)1865 d)1880
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 Apr 2008 20:11:19 IST
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yaar i found this ques in viteee sample questions with the options as i have given
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answer is b
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 Apr 2008 20:16:08 IST
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ya but tell me how???????????
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 Apr 2008 20:20:46 IST
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how????????????
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 Apr 2008 20:26:15 IST
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hello?????????/so gaye!!!!!!!!!!!
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 Apr 2008 20:32:15 IST
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 Apr 2008 23:42:26 IST
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could u please explain ( sboosy) how it is 5 or 5^2???
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 Apr 2008 23:47:21 IST
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see we have 2*3*5*5*7 ...now what i m saying is that .. first number could be (2*3*5*7)*5*1*1*1 or the other 5 could also go in ..since 5 is a repeat ..we have to consider combinations
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