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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: The remainder when x=1! + 2! + 3! + 4!+ .....+ 100! is divided by 240 is
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payal1spark (0)

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The remainder when x=1! + 2! + 3! + 4!+ .....+ 100! is divided by 240 is
    
payal1spark (0)

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Pleeeez reply soon....options are:


153







pleeez.....tell me how to solve it...

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animal (562)

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is the ans 153.


tell me if i m right then i will explain

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allamraju (2960)

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Ans is 153,bcoz 1!+2!+3!+4!+5!+720+......=1+2+6+24+120+240k where k is a constant=153+240k.Hence the ans.

MAKING A MISTAKE IS HUMAN BUT REPEATING IT IS IDIOTIC.
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sachinsethi21 (11)

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i guess the answer is 153...


am i rite ?

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GoNik (136)

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i think its 153........allamraju is correct
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payal1spark (0)

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yeah u r all rite......


thnks...

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