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![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 Dec 2007 18:00:27 IST
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If z1 and z2 are the non-real complex roots of ax2+bx+c=0 (0<a<b<c), prove |z1|>1,|z2|>1
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 Dec 2007 18:52:18 IST
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if this quad. eqn. has complex roots then they will exist in conjugate pairs
so, let x+iy=z1 nd x-iy=z2 be the two roots
so from here u get the product of roots= c/a >1 (as given) as the product of roots= (x^2+y^2)>1 so lz1l,lz2l>1
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 Dec 2007 04:05:30 IST
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---sorry 4 my silly q--------
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IF U THINK U CAN, U CAN........IF U THINK U CAN'T, U CAN'T.........
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 Dec 2007 08:26:54 IST
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c>a so c/a is greater than 1
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