IIT JEE , AIEEE Forum - Mathematics , Algebra

trisha

Two persons each make a throw with a pair of die .let p be the probability that their throws are equal.find the value of 648p.

001sri

ans is 18?

trisha

can u tell how u got it.actually i dont know answer

Asmita

Fav. outcomes,n(E)=6

Total possible outcomes,n(S)=6*6=36

Thus p=1/6

So 648p=648*1/6

=108

I hope u got it.

trisha

asmitha u misunderstood the question.plz read it once again.

Asmita

Sorry 4 that

p=C(36,1)*1/(36*36)

=1/36

So 648p=648*1/36

=18

Asmita

I hope this time i m correct.

edison

Thats perfect Asmita. Keep sharing our load.

Thank you.

trisha

i cant understand correctly.plzz explain me elaborately dear asmitha

i cant understand the the following step

p=C(36,1)*1/(36*36).

how u got that step please explain me

ranjitghumde

here random expriment is two person tossed coin simultaneously, so possible outcome is { (1,1) (1,1), (1,2)(1,1),...............(6,6)(6,6)}. so num of possible outcome is 36 * 36.

E be the event that both person getting same outcome .

i.e. {(1,1)(1,1) , (1,2)(1,2) , .......................(6,5)(6,5) , (6,6)(6,6) }

n(E) = 36

P(E) = 36/ 36 * 36

=1/ 36

SO 648P = 1/36 * 648

= 18

trisha

ranjit,i accept.thank u very much

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