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![[Post New]](/templates/default/images/icon_minipost_new.gif) 4 Apr 2008 19:47:21 IST
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Draw the graph of the function- y=[x] + |1-x|, -1<=x<=3 and determine the points, if any, where this function is not differentiable.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 4 Apr 2008 19:54:07 IST
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ne1 plz.............
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see i do not have the resource to draw the graph but it is easy
first it is non-differentiable at all integral points...
to draw this graph use the following information 1. draw the graph of mod(1-x) 2. use the fact that period of [x] is 1 for ex-
in interval (0,1) , f(x) = mod (1-x) in (1,2) , f(x) = 1 + mod (1-x) . . . . in interval (99,100) , f(x) = 99 + mod (1-x) and so on ....
rate me if useful
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 4 Apr 2008 20:11:11 IST
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thanx dude...............
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