Algebra

sathyaram's Avatar
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27 Mar 2012 09:30:43 IST
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Tough one! lets c who can do it !
Engineering Entrance , JEE Main , JEE Main & Advanced , Mathematics , Algebra

  Find the value of the sum:
\frac{1}{1+2} + \frac{2}{1+2+3} +\frac{3}{1+2+3+4 }+......+\frac{2011}{1+2+3+4+....+2010+2011}



Comments (11)

hemang's Avatar

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27 Mar 2012 10:44:06 IST
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no simple method to do it..

i don't understand a word of it..

:)

copied it from wolfram alpha so that people don't waste their time on this question.

 


Hot goIITian

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27 Mar 2012 11:22:26 IST
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macha .. best is calculus approach :) 

 


Hot goIITian

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27 Mar 2012 11:27:54 IST
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2010/2011 ??? ?? ??


Hot goIITian

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27 Mar 2012 11:29:55 IST
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@ hemang  -- what is wolfram alpha

santanu sinha's Avatar

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27 Mar 2012 11:33:01 IST
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no man! the first four terms sum up to get something more than 2010/2011
sathyaram's Avatar

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27 Mar 2012 12:28:30 IST
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 @ srinivasan: MAcha,its a calculating engine which express the no. For ex,u eant to find the reminder when 2^44 is divided by 4,u csn paste it on the wolfram website,It will actually be,refer this linkle to find out...http://www.wolframalpha.com/input/?i=2%5E44+mod+3 


Hot goIITian

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27 Mar 2012 12:55:45 IST
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@sathya - thanks machi its nice website :)


Scorching goIITian

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27 Mar 2012 14:19:47 IST
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while solving i am getting two harmonic progression's which sum is impossible to exactly calculate.
sathyaram's Avatar

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27 Mar 2012 20:00:54 IST
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2\sum_{k=1}^{n+2} \frac {1} {k} - 4 + \frac {2} {n+2}            


Scorching goIITian

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28 Mar 2012 14:51:58 IST
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@satyaram it is a harmonic series and couldn't be summed.
pooja garg's Avatar

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28 Mar 2012 14:58:26 IST
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plz explain how it could b solved



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