IIT JEE , AIEEE Forum - Mathematics , Algebra

ankur.kkhurana

A is product of 10 consecutive 10 digits no. .Y is highest power of 5 in A.what is maximum value of Y.

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taruntanuj007

Cud u pllz state the question a bit properly i cudnt get it do u mean

A= products of 10 conseutive 10 digit integers and Y is its maximum power to which 5 is raised then find Y;

Do reply

umang

Hey ankur !

I am also a regular solver of brainstorm . Did u get the rest of the questions in today's brainstorm ?????

pink_ele

what's a brainstorm?????????????

sudeep.kumar

In any set of ten consecutive no.s, there are two numbers divisible by 5..

Now if one of them is a power of five, then we have more no. of 5 as factor of A

We find that 5¹⁴ = 6103515625, which is a ten digit no.
So if we take any set of 10 no.s which includes this no. (5¹⁴), then it will have the maximum possible no. of 5 as factors...... and the no. of 5's will be 14 + 1 = 15

(we dont take 5¹³as a ten digit no., because it will give only 14 5's in A)

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