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 Community Discussion Question:
TRIGNO
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 30 Jan 2008 22:59:27 IST
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TAN 6(20) -33 TAN420+27 TAN2 20 = 1,0,2,3(CHOOSE ONE)
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26 Feb 2008 23:35:04 IST
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tan(3a) = (3tana - tan3a)/ (1-3tan2a) so tan (60) =  3 = (3tan20 - tan 320)/(1-3tan 220) so cross multiplying and simplifying tan 320 - 3 3tan 220 - 3tan20 + 3 = 0 (tan 320 - 3 tan20) = (3 3tan 220 - 3) squarring on either side tan620 - 6 tan4 20 + 9tan220 = 27tan420 - 18tan220 + 3 so tan620 - 33tan420 +27tan220 = 3
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