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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 Feb 2007 19:46:12 IST
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Q.1 if A,B,C are the angles of a triangle ABC and <A is obtuse, then :: a. tan C tan B < 1 b. tan B tan C >1 c. tan B tan C = 1 d. nonw of these
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 Feb 2007 20:02:11 IST
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please reply !!
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 Feb 2007 20:11:11 IST
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!!!???
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 Feb 2007 20:17:16 IST
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answer is A (just substitute and see),after all its an mcq!
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Destiny is what you make
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 Feb 2007 20:18:34 IST
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but how can we think of the proof ??
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 Feb 2007 20:19:19 IST
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hye amaron, please try other questions asked by myself if u are not busy !
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 Feb 2007 20:23:43 IST
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Acc. to me - tanA should be -ve , bcoz A is obtuse (b/w 90 and 180) and tan B should be +ve (as it is acute) therefore , tanAtanB is -ve . this means tanAtanB is < 0 that is , answer should be D (none of these )
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Umang |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 Feb 2007 20:25:12 IST
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it is not Tan A> tanB. the questionsis asking to prove ::
tanB tanc<1
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 Feb 2007 20:36:38 IST
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Hey , I got it ! tan(B+C) = tanB + tanC / 1-tanBtanC this means -tanA = tanB+tanC/1-tanBtanC (A+B+C = pi) tanA is -ve . therefore , LHS is +ve . In RHS , tanB+tanC is +ve . therefore , 1-tanBtanC is +ve this means tanBtanC is less than 1 . Is this clear ?????
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Umang |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 Feb 2007 20:37:08 IST
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can anyone solve ??
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 Feb 2007 20:37:47 IST
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SORRY I READ THE QUESTION WRONG newayzz i'll go with umang
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dbznfreak---watchin episodes for 6 yrs--movin on to dbgt
<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
<TR><TD>
<DIV ALIGN="right">Animated Letters</DIV></TD></TR></TABLE>
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 Feb 2007 20:38:05 IST
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I am sorry , earlier I wrongly read the question !!!
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Umang |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 Feb 2007 20:39:22 IST
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