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Ask iit jee aieee pet cbse icse state board experts Expert Question: trigonometry
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vish0001 (493)

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Q.1 if A,B,C are the angles of a triangle ABC and <A is obtuse, then ::
 
a. tan C tan B < 1                    b. tan B tan C >1
c. tan B tan C = 1                    d. nonw of these



    

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vish0001 (493)

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please reply !!



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vish0001 (493)

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!!!???



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amaron (726)

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answer is A (just substitute and see),after all its an mcq!

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vish0001 (493)

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but how can we think of the proof ??



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vish0001 (493)

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hye amaron, please try other questions asked by myself if u are not busy !



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umang (229)

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Acc. to me -
tanA should be -ve , bcoz A is obtuse (b/w 90 and 180)
and tan B should be +ve (as it is acute)
therefore , tanAtanB is -ve .
this means tanAtanB is < 0
that is , answer should be D (none of these )

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vish0001 (493)

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it is not Tan A> tanB. the questionsis asking to prove ::

tanB tanc<1



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umang (229)

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Hey , I got it !
tan(B+C) = tanB + tanC / 1-tanBtanC
this means -tanA = tanB+tanC/1-tanBtanC (A+B+C = pi)
tanA is -ve . therefore , LHS is +ve .
In RHS , tanB+tanC is +ve . therefore , 1-tanBtanC is +ve
this means tanBtanC is less than 1 .
Is this clear ?????

Umang
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vish0001 (493)

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can anyone solve ??



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vasanth (2315)

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SORRY I READ THE QUESTION WRONG
newayzz i'll go with umang

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umang (229)

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I am sorry , earlier I wrongly read the question !!! 

Umang
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