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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: triplets
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neeraj_agarwal_1990 (887)

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The equation has
a)at least 1 real solution
b)at least 3 real solutions
c)exactly one real solution
d)All of these

ans-c
i am getting x= 2 and as the solutions of this equation (taking log on both sides)
    
Conjurer (615)

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Re:triplets

How do I use LATEX here?

Obviously there cannot be 2 real roots(it may have 3) to this equation as it is cubic.


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neeraj_agarwal_1990 (887)

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i am getting x=2 as a double root....
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RyuAmakusa (714)

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there are 3 roots 2, 2^-1/3, 1/4
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RyuAmakusa (714)

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 take log with base 2 on both sides. let log2 x = t
on taking log u get (3/4t2 + t - 5/4)t = 1/2 => 3t3 +4 t2 -5t -2 =0.
=> 3t3 +6 t2 -2 t2  -4t -t -2 =0.
=>3t2(t+2) -2t(t+2) -(t+2) =0
=>(t+2)(3t2 - 2t -1)=0
=>(t+2)(3t+1)(t -1)=0
=> t = 1,-1/3,-2.
so log2 x =1,-1/3,-2. => x= 2,2-1/3,2-2.
so 3 roots.
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