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![[Post New]](/templates/default/images/icon_minipost_new.gif) 5 Apr 2008 17:48:00 IST
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try this....
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5 Apr 2008 17:49:21 IST
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a natural no is selected frm 1 to 1000 at random then the prob that a particular non zero digit appears at most once is..
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5 Apr 2008 17:55:47 IST
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there are 10 digits... its a natural no which is selected...implies no zero..
p=1
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Here I am this is ME!!...and there's no where else on earth I'd rather be!!!!!! |
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5 Apr 2008 17:57:06 IST
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..........
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5 Apr 2008 17:58:57 IST
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the ans is 243/250
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total numbers from 1 to 1000 that contains a non zero number atleat 2 or 3 times can be of 3 type xxy,xyx,yxx x is that non zero no. and y can assume 9 values (from 0 to 9 except x) total numbers 27+1(xxx)=28 p1=28/1000=7/250 your required probability=p2=1-p1 =243/250 rate me...................
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