IIT JEE , AIEEE Forum - Mathematics , Algebra - try this one

ridhima

the no. of solutions of x^2 -2 -[x] =0
plz give the methord to solve this

nishantxman

put the 4 options and see which satisfies the eqn

ridhima

plz don't post such short cuts
plz give a solution to this

rathin_123

it may be solve by critical point methord

srini

.Hey,

If x E I => x²-x-2=0=>

x=-1 or 2

If x

I => x²-[x]-2=0 x²-x-2+{x}=0

Since for {x}: 0<{x}<1 => -1<x²-x-2<0

= -1<(x-1/2)²-9/4<0

x-1/2>

5 /2 -3/2<x-1/2<3/2

Here, dont take integral solutions

.

ashish_banga

x^2 - 2 - [x] = x^2 - 2 -( x - {x} )

{x} = fractional part of x = - x^2 + 2 + x
as 0< {x} <1
0 < - x^2 + 2+ x < 1
solve to get answer it is simple afterwards

PLEASE RATE ME

ridhima

thnx
got it

ashish_banga

i get (^{[ ]}

5 + 1) /2 < x < 2

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