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![[Post New]](/templates/default/images/icon_minipost_new.gif) 4 Jun 2007 13:05:12 IST
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show that the equation x4+4x3-4x-13=0 has two real roots only and find the position of roots.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 4 Jun 2007 15:51:02 IST
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by rule of sighns it is obvi since it has a root in [-4,-3] it has another root in [1,2]
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i may not be able to give the best solution!
But i can definetly give a good solution! |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 4 Jun 2007 19:34:54 IST
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hey can ne one tell whts this descartes rule of signs plzzzz explain ............
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there is no right way 2 do something wrong !!!!!!!! |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 4 Jun 2007 19:41:33 IST
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ya what is descartes rule of sign
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adversities cause some men to break other to break records............i m of the other type....... :-) |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 4 Jun 2007 20:36:43 IST
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mr.irlmaks , since 1,2,-3,-4 are smaller numbers we can locate two roots by trial and error method.But my question is that the other two roots may also be real and they may be in some intervel like (-33325226,-48888893) and (-2543412321,-9475836752) i.e., how can we say that other two roots are not real?
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 4 Jun 2007 22:05:24 IST
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descartes rule is a method of determining the maximum number of positive and negative real roots of a polynomial. For positive roots, start with the sign of the coefficient of the lowest (or highest) power. Count the number of sign changes n as you proceed from the lowest to the highest power (ignoring powers which do not appear). Then n is the maximum number of positive roots. Furthermore, the number of allowable roots is n, n-2, n-4 .... For example, consider the polynomial Since there are three sign changes, there are a maximum of three possible positive roots. For negative roots, starting with a polynomial f(x), write a new polynomial f(-x) with the signs of all odd powers reversed, while leaving the signs of the even powers unchanged. Then proceed as before to count the number of sign changes n. Then n is the maximum number of negative roots. For example, consider the polynomial and compute the new polynomial In this example, there are four sign changes, so there are a maximum of four negative roots.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 4 Jun 2007 22:14:51 IST
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trisha thats flithy see by rule of signs it has a max. of one +ve and one -ve root existance can be checked by differentiation meathods like increasing..... etc
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i may not be able to give the best solution!
But i can definetly give a good solution! |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 5 Jun 2007 07:53:32 IST
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mr.irlmaks , plz keenly observe there are three sign changes in f(-x) that implies atmost 3 negative roots.how can u say that ther is only one negative root? magiclko or any expert plz solve this for me..
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