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![[Post New]](/templates/default/images/icon_minipost_new.gif) 6 Sep 2007 20:11:32 IST
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value of i raise to power i where i is
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6 Sep 2007 20:16:29 IST
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if i is iota ans is e^ -pi/2
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6 Sep 2007 20:17:20 IST
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use euler's formulaeone time...
e^ i. (pie/2).i
i.i = -1
i^i = e^-pie/2
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padhna likhna chad de mitra , nakal te rakhi aas , chak chaddar te so ja bhagta , Rabb karega tennu paas.....
PLZ NEVER EVER RATE ME FOR MY ANSWERS , IF U WANT TO COMPLIMENT ME THEN JUST BEAT UR HEAD & SAY
"YEH KIS PAGAL NE MERA QN. SOLVE KER DIYA"
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EVEN SERIOUS ^ INFINITY
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Shubham
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6 Sep 2007 20:21:41 IST
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Let Z=ii and taking log to the base e on both sides,then log(z)=ilog(i) =i.iPi/2=-pi/2 (Since i=eipi/2) z=e-pi/2
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***T.Venkat*** |
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6 Sep 2007 20:23:41 IST
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is logarithm defined for complex nos??
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Cogito, ergo sum
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........... Chalie Spencer Chaplin |
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6 Sep 2007 20:30:54 IST
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@vidyun_dusa
no logarithms are only defined for real no.s///
domain (0,infinity)
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padhna likhna chad de mitra , nakal te rakhi aas , chak chaddar te so ja bhagta , Rabb karega tennu paas.....
PLZ NEVER EVER RATE ME FOR MY ANSWERS , IF U WANT TO COMPLIMENT ME THEN JUST BEAT UR HEAD & SAY
"YEH KIS PAGAL NE MERA QN. SOLVE KER DIYA"
I AM SERIOUS!!!!
EVEN SERIOUS ^ INFINITY
PLZZZZZZ NEVER RATE ME....HOPE U WILL UNDERSTAND....
Shubham
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6 Sep 2007 20:50:44 IST
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Logarithm is defined for complex nos. also.
if z=x+iy
log(z)= log |z| + i tan-1(y/x)
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6 Sep 2007 22:15:57 IST
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U are right nadeemoidu.
In the real field Logarithm domain is (0,infinity).
In the complex field domain of logarithm is C (Set of complex nos.)
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***T.Venkat*** |
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