Let
ARp-1 = a , ARq-1=b and ARr-1=c
where A and R are the first term and common ratio of the G.P.
take log on both sides
u get
logA + (p-1)logR=loga....(1)
logA + (q-1)logR=logb.....(2)
logA + (r-1)logR=logc......(3)
subtract (3) from (2)
u get (q-r)=(logb-logc)/logR
subtract (1)from (3)
(r-p)=(logc-loga)/logR
and subtract (2) from (1)
(p-q)=(loga-logb)/logR
Substitute the values of (p-q), (r-p ) and (q-r) in the vector eqn.
take dot product between two vectors.
u get
2loga[(logb-logc)/logR] + 2logb[(logc-loga)/logR] + 2logc[(loga-logb)/logR]=0
thus angle will be pie/2