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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: Viete's formulae
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hsbhatt (6235)

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If a, b and c are the roots of the equation
 
x3-mx+19 = 0, find a3+b3+c3.

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avi_1214545 (974)

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is it -57??

Na pine ka shouk tha na pilane ka shonk tha. Hume to sirf NAZREIN milane ka shonk tha. Par kya karen hum nazre hi unse mila baithe jinhe nazron se PILANE ka shonk tha.
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hsbhatt (6235)

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method please!

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avi_1214545 (974)

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from thoery of roots we get
a+b+c=0
ab+bc+ac=-m
abc=-19

now

a3 + b3 + c3 - 3abc = (a+b+c)(a2 +b2 + c2 -ab -bc -ac)

since a+b+c=0

a3 + b3 + c3 = 3abc = 3*-19= -57

Na pine ka shouk tha na pilane ka shonk tha. Hume to sirf NAZREIN milane ka shonk tha. Par kya karen hum nazre hi unse mila baithe jinhe nazron se PILANE ka shonk tha.
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avi_1214545 (974)

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rate if satisfied.....

cheeeerzz

Na pine ka shouk tha na pilane ka shonk tha. Hume to sirf NAZREIN milane ka shonk tha. Par kya karen hum nazre hi unse mila baithe jinhe nazron se PILANE ka shonk tha.
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narayana (0)

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hey man it is -57
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hsbhatt (6235)

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Ok now I change the equation to
 
x3-5x2+8x-2 = 0
 
Now find a3+b3+c3

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avi_1214545 (974)

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now it comes as 11

Na pine ka shouk tha na pilane ka shonk tha. Hume to sirf NAZREIN milane ka shonk tha. Par kya karen hum nazre hi unse mila baithe jinhe nazron se PILANE ka shonk tha.
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avi_1214545 (974)

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now
a+b+c = 5
ab+bc+ac = 8
abc = 2

same as above

a3+b3+c3 - 3abc = (a+b+c)(a2+b2+c2 -ab-bc-ac)

a3+b3+c3 = 5(25-3*8)+6 = 11

Na pine ka shouk tha na pilane ka shonk tha. Hume to sirf NAZREIN milane ka shonk tha. Par kya karen hum nazre hi unse mila baithe jinhe nazron se PILANE ka shonk tha.
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