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Algebra
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5 May 2011 13:04:39 IST
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see gal one person has already told one way to get to the ans easily
but for beginers i would sugest the folowing way
u hv got 4^87 / 3
= 4.4.4. ..................4.4.4 87 times divided by 3
=4/3 4^86
=(1+ 1/3) 4^86
=4(1+1/3)4^85
=(4+4/3)4^85
=(4+1+1/3)4^85
=(5+1/3)4^85
=(20+4/3)4^84
=(21+1/3)4^84
...........................
..................
=(k+1/3) where k is a constant
hence remainder is 1
now try this one
its a bit tricky
5555^2222 + 2222^5555 when divided by seven gives remainder = ? ans is 0













dear friend, this question involves using the binomial theorem. on writing 4^87 as (3+1)^87 we can expand it as C(87,0) * 3^87 + C (87,1) * 3^86 + C(87,2) * 3^85 + ............................. + C (87,87) we can easily see that all terms are divisible by 3 but the last one that is (87,87) that is 1 is not. so the remainder will be 1... rate me.....