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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 May 2008 21:12:40 IST
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d no. of ways in which any 4 letters can b selected frm d word "CORGOO" is
d no of ways of 7 digit no d no. d sum of whose digits is even
d no.of no.s smaller dan 104 in d decimal notation of which all d digits r different is
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 May 2008 21:17:51 IST
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q.1 3c1 + 3c2 + 3c3 = 7
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 May 2008 21:22:11 IST
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q.3 9.9.8.7 + 9.9.8 + 9.9 +9
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 May 2008 21:25:40 IST
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q3 9.9.8.7
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 May 2008 21:27:52 IST
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@ ryu.. it's not necessarily a 4 digit number
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 May 2008 21:34:28 IST
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oh then the ans is infinity ......but i dont know i should have noted 4 digit no. as mukund said and also i should have said infinity at the first time ....my skill has decresed i guess..
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 May 2008 21:34:54 IST
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q2) no of such natural nos = 7 dig nos with 0 odds + 2 odds + 4odss + 6 odds (including 0 at 7th place) - 6 dig nos with 0 odds + 2 odds + 4 odds + 6 odds (including 0 at 6th place) =5^7(7C0 + 7C2 + 7C4 + 7C6) - 5^6(6C0 + 6C2 + 6C4 + 6C6)
*not so sure
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<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
<TR><TD>
<DIV ALIGN="right">Animated Letters</DIV></TD></TR></TABLE>
I am only one,
But still I am one.
I cannot do everything,
But still I can do something;
And because I cannot do everything
I will not refuse to do the something that I can do.
- Edward Everett Hale
Rahul Dey
Dept. of Electronics & Electrical
Communication Engineering,
IIT Kharagpur
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 May 2008 22:47:20 IST
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It isn't infinity dude.. Less than 10^4 means 4 digit numbers, 3 digit numbers, 2 digit numbers and 1 digit numbers. Check out my answer above
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 May 2008 22:49:51 IST
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Second question looks alright to me..
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 May 2008 23:20:33 IST
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even if i ASSUME what u say is true then what about 0 is 0 not a 1 digit no.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 May 2008 23:21:59 IST
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It's not a natural number.. In number problems we generally speak only of natural numbers and not whole numbers
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 May 2008 23:46:18 IST
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1) = 7 there are 3Os so when we select all the Os, no of selections of the fourth letter = 3C1 when 2 Os are selected, no. of selections of other 2 = 3C2 similarly case 3
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