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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 Oct 2007 08:46:51 IST
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what is remainder when 23^23 is devided by 53?
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 Oct 2007 11:29:53 IST
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9.9811321
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 Oct 2007 11:56:45 IST
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hey buddy answer is 30.
if u want detailed answer do ask (hint is 23^2 =53*9+52.now use binomial & get 23^4=53*n +1 and so to 23^22=53*n+52 &hence 23^23=53*n + 30
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