Home » Ask & Discuss » Mathematics. » Algebra « Back to Discussion

Algebra

New kid on the Block

Joined:	26 Dec 2007
Post:	1

26 Dec 2007 10:46:02 IST

0 People liked this

615

when 43 raise to power 43 is divided by 37 ,what is the reminder?

None

when 43 raise to power 43 is divided by 37 ,what is the reminder?

Share this article on:

Comments (8)

Priyesh

Blazing goIITian

Joined: 18 Feb 2007

Posts: 1042

26 Dec 2007 10:55:15 IST

Like 1 people liked this

write 43^43

(37 + 6)^43

now expand binomially

the remainder will come only from the last term ⁴³C₄₃ 6⁴³

surbhi mittal

New kid on the Block

Joined: 11 Jul 2007

Posts: 15

26 Dec 2007 11:14:47 IST

Like 0 people liked this

Priyesh is rite..........i go by his answer.........

Akshay Pamnani

Blazing goIITian

Joined: 27 Nov 2007

Posts: 470

26 Dec 2007 11:17:42 IST

Like 0 people liked this

nice answer Priyesh

Cool gay

Blazing goIITian

Joined: 13 Aug 2007

Posts: 687

26 Dec 2007 14:08:04 IST

Like 0 people liked this

priyesh sabse bada 'gadha' hai aur jo use support kar rahein hain woh bhi

bhaisaab 6^43 ko further 37 se divide nahi kar sakte kya. foolish people

A K

Cool goIITian

Joined: 21 Dec 2007

Posts: 33

26 Dec 2007 14:11:58 IST

Like 1 people liked this

6^43=36^21*6= (37-1)^21*6 =37k-6 so the remainder is 31 ....

Priyesh

Blazing goIITian

Joined: 18 Feb 2007

Posts: 1042

26 Dec 2007 14:37:26 IST

Like 0 people liked this

hey sree

who said we can't divide it further i have just said that the remainder will arise from the last term.rest division can be done by the author himself.

i have nowwhere written that answer is the last term obviously remainder wil be less than 37

also do mind ur language

Cool gay

Blazing goIITian

Joined: 13 Aug 2007

Posts: 687

26 Dec 2007 19:01:19 IST

Like 0 people liked this

Yaar srry for that rough stuff.

i was in tension so i wrote that. purpose was nt to hurt u yaar . i am really srrry

i promise this will nt be repeated in future

if u are satisfied that u can nudge me.

bye

nitigya

Scorching goIITian

Joined: 5 Dec 2006

Posts: 225

26 Dec 2007 20:07:19 IST

Like 1 people liked this

write 6⁴³as 6(36)²¹

=6(37-1)²¹ = expanding it binomially we get

37i - 6 where i is an integer

=37i-6+37-37

=37i+31

hence remainder should be 31

Quick Reply

Reply

	Some HTML allowed.
	Keep your comments above the belt or risk having them deleted.
	Signup for a avatar to have your pictures show up by your comment
	If Members see a thread that violates the Posting Rules, bring it to the attention of the Moderator Team