Algebra

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26 Dec 2007 10:46:02 IST
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when 43 raise to power 43 is divided by 37 ,what is the reminder?
Engineering Entrance , JEE Main , JEE Main & Advanced , Mathematics , Algebra

when 43 raise to power 43 is divided by 37 ,what is the reminder?



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Priyesh's Avatar

Blazing goIITian

Joined: 18 Feb 2007
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26 Dec 2007 10:55:15 IST
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write 43^43
as
(37 + 6)^43
 
now expand binomially
 
the remainder will come only from the last term 43C43 643
surbhi mittal's Avatar

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26 Dec 2007 11:14:47 IST
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Priyesh is rite..........i go by his answer.........
Akshay Pamnani's Avatar

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Joined: 27 Nov 2007
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26 Dec 2007 11:17:42 IST
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nice answer Priyesh
Cool gay's Avatar

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26 Dec 2007 14:08:04 IST
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priyesh sabse bada 'gadha' hai aur jo use support kar rahein hain woh bhi

bhaisaab 6^43 ko further 37 se divide nahi kar sakte kya. foolish people
A K's Avatar

Cool goIITian

Joined: 21 Dec 2007
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26 Dec 2007 14:11:58 IST
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6^43=36^21*6= (37-1)^21*6 =37k-6 so the remainder is 31 ....
Priyesh's Avatar

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26 Dec 2007 14:37:26 IST
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hey sree
who said we can't divide it further i have just said that the remainder will arise from the last term.rest division can be done by the author himself.
 
i have nowwhere written that answer is the last term obviously remainder wil be less than 37
 
also do mind ur language
Cool gay's Avatar

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Joined: 13 Aug 2007
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26 Dec 2007 19:01:19 IST
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Yaar srry for that rough stuff.

i was in tension so i wrote that. purpose was nt to hurt u yaar . i am really srrry

i promise this will nt be repeated in future

if u are satisfied that u can nudge me.

bye
nitigya's Avatar

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Joined: 5 Dec 2006
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26 Dec 2007 20:07:19 IST
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write 643 as 6(36)21
 
=6(37-1)21 = expanding it binomially we get
 
37i - 6 where i is an integer
 
=37i-6+37-37
=37i+31
hence remainder should be 31



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