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Joined:	25 Aug 2011
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25 Aug 2011 17:50:01 IST

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Engineering Entrance , JEE Main , JEE Advanced , Mathematics , Algebra

Find five consecutive numbers whose product is 720.

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Yagyadutt Mishra

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Joined: 19 Feb 2009

Posts: 1979

25 Aug 2011 19:18:33 IST

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It is basically very conceptual question !

(a)(a+1)(a+2)(a+3)(a+4)(a+5) = 720
(a)(a+1)(a+2)(a+3)(a+4)(a+5)=1X2X3X4X5X6 ( since 1X2X3X4X5X6=720 )

hence a = 1
And consecutive numbers equal to 1,2,3,4,5,6,

hemang

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Joined: 27 Dec 2010

Posts: 1508

26 Aug 2011 10:26:39 IST

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actually sir i think the 5 consecutive numbers are 2,3,4,5,6 and not 1,2,3,4,5,6.

:-)

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