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![[Post New]](/templates/default/images/icon_minipost_new.gif) 22 Jun 2008 12:26:22 IST
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x= no. of boys in class & y=no. of girls then find total no. of students if xy=2x-y
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 22 Jun 2008 13:00:11 IST
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edited
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God does not care about our mathematical difficulties. He integrates empirically. ~~~Albert Einstein (1879-1955)~~~~
To divide a cube into two other cubes, a fourth power or in general any power whatever into two powers of the same denomination above the second is impossible, and I have assuredly found an admirable proof of this, but the margin is too narrow to contain it.~~~Pierre de Fermat (1601-1665)~~~
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 23 Jun 2008 21:31:58 IST
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ans:
let x=1
so we get y=1
so total=2
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 23 Jun 2008 21:41:34 IST
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We have to find X+Y, and not necessarily X and/or Y, By moulding the given equation, it comes out to be X+Y = (X+3)*Y/2 So the no. of students is (X+3)*Y/2. It is not asked to give the no. of students in terms of constants.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 23 Jun 2008 21:50:34 IST
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xy=2x-y adding x to both sides
x(x+y)=3x-y x+y=(3x-y)/x
rate if useful...
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 23 Jun 2008 22:14:55 IST
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i think ur ques might hv some mistake... as it contains 2 variables and having only one equation!!!
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 24 Jun 2008 12:15:53 IST
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yes its true. how can a single equation having 2 variables solved
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 25 Jun 2008 17:26:15 IST
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y=2x/(x+1)...
x=odd since the numerator is even...and y a natural no.
that means x+1 (even ) divides 2 * an odd no.. hence x+1=2 .. or x=1 so y=1. total students =2
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