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Analytical Geometry

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Joined: 16 Aug 2009
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16 Aug 2009 13:48:20 IST
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distance beetween two parallel lines x-1/2=y-2/3=z-3/4 and x-2/4=y-3/6=z-4/8
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distance beetween two parallel lines x-1/2=y-2/3=z-3/4 and x-2/4=y-3/6=z-4/8


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C!-!!NMAY's Avatar

Blazing goIITian

Joined: 30 Mar 2008
Posts: 1415
16 Aug 2009 14:42:39 IST
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is the answer is root(6/29)
C!-!!NMAY's Avatar

Blazing goIITian

Joined: 30 Mar 2008
Posts: 1415
16 Aug 2009 15:11:25 IST
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 see , i m telling approach,,,,,,,,

consider first eqn as line 1 and second as line 2

as given in question line 1 is passing thru Q(1,2,3).......and suppose P be a point on line two whose coordinate can be written as (4r+2,6r+3,8r+4)........now write drs of PQ,,,,,,,,and apply perpendicular condition PQ*line2=0 from here u will get r and P also,,,,now apply distance formula and get PQ,,,,,,,

Soumen Goswami's Avatar

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Joined: 10 Apr 2007
Posts: 1777
16 Aug 2009 22:59:05 IST
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The approach suggested by C!-!!nmAY is correct

Piyush Bhatia's Avatar

Hot goIITian

Joined: 29 Jan 2008
Posts: 131
17 Aug 2009 20:17:50 IST
1 people liked this

  see , i m telling approach,,,,,,,,

consider first eqn as line 1 and second as line 2

as given in question line 1 is passing thru Q(1,2,3).......and suppose P be a point on line two whose coordinate can be written as (4r+2,6r+3,8r+4)........now write drs of PQ,,,,,,,,and apply perpendicular condition PQ*line2=0 from here u will get r and P also,,,,now apply distance formula and get PQ,,,,,,,   

 

 C!-!!nmAY is correct!




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