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Analytical Geometry
Find distance of point (-3,4,-4) from the line (x+2)/3 = (2y+3)/4 = (3z+4)/5 measured parallel to the plane 4x + 12y -3z +1 =0
Let (-3,4,-4) = P.Let Q be a general point on line.So Q = (3k-2,(4k-3)/2,(5k-4)/3)As PQ is parallel to plane so it is perpendicular to normal to plane (n) = 4i+12j-3kPut n.PQ = 0 and solve to get kDistance parallel to plane is length PQ.
Let (-3,4,-4) = P.
Let Q be a general point on line.
So Q = (3k-2,(4k-3)/2,(5k-4)/3)
As PQ is parallel to plane so it is perpendicular to normal to plane (n) = 4i+12j-3k
Put n.PQ = 0 and solve to get k
Distance parallel to plane is length PQ.
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Let (-3,4,-4) = P.
Let Q be a general point on line.
So Q = (3k-2,(4k-3)/2,(5k-4)/3)
As PQ is parallel to plane so it is perpendicular to normal to plane (n) = 4i+12j-3k
Put n.PQ = 0 and solve to get k
Distance parallel to plane is length PQ.