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Analytical Geometry

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18 Feb 2010 22:41:34 IST
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Find the minimum distance between the curves y^2 = x-1 and x^2 = y-1
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Find the minimum distance between the curves y^2 = x-1 and x^2 = y-1


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C!-!!NMAY's Avatar

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Nehal Wani's Avatar

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18 Mar 2010 16:51:00 IST
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Both the parabolas are symmetric to the line x=y.

Therefore, equating their slopes to 1,

for parabola x^2=y-1,

dy/dx = 1

2x =1

x=1/2

corresponding value of y by putting the value of x in the eq. of parabola we get y=5/4

Similarly, for the parabola y^=x-1,

dx/dy =1

2y=1

y=1

corresponding value of x by putting the value of y in the eq. of parabola we get x=5/4

The minimum distance is between the points (1/2,5/4) and (5/4,1/2)

And 32/4

 

FORESTS's Avatar

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19 Mar 2010 12:24:52 IST
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 have a salute from me NEHAL WANI

Nehal Wani's Avatar

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20 Mar 2010 15:18:39 IST
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 Thanks For The Salute, Amritpal. I think you have also posted the same question on askiitians.com


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Joined: 25 Mar 2010
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26 Mar 2010 11:25:05 IST
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 minimum distance between any to curves is along the common normal

Yagyadutt Mishra's Avatar

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26 Mar 2010 13:25:56 IST
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Minimum distance is calculated along the common normal of both the curves......

 

All the above solutions posted by users are correct....

Best wishes !!


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31 Mar 2010 10:50:01 IST
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