Home » Ask & Discuss » Mathematics
« Back to Discussion

Analytical Geometry

New kid on the Block

Joined:	11 Jun 2012
Post:	2

11 Jun 2012 14:32:16 IST

0 People liked this

327

find the point on x axis equidistant from (7,6) and (-3,4)

Engineering Entrance , JEE Main , JEE Advanced , Mathematics , Analytical Geometry

find the point on x axis equidistant from (7,6) and (-3,4)

Comments (1)

Vikram Saxena

Blazing goIITian

Joined: 1 Apr 2007

Posts: 4025

11 Jun 2012 17:13:00 IST

Like 0 people liked this

assume any point on x axis say (x,0)........

this point is equidistant from given points that means............((x-7)(square)+(0-6)(square))root=((x+3)(square)+(0-4)(square))root

on solving....x(square)+49-14x+36=x(sq)+9+6x+16.........

equating,,,,,,,85-25=20x

60=20x

x=3........so (3,0) is the requiredpoint..............

Quick Reply

Reply

	Some HTML allowed.
	Keep your comments above the belt or risk having them deleted.
	Signup for a avatar to have your pictures show up by your comment
	If Members see a thread that violates the Posting Rules, bring it to the attention of the Moderator Team

Free Sign Up!

Preparing for JEE?

Kickstart your preparation with new improved study material - Books & Online Test Series for JEE 2014/ 2015

@ INR 5,443/-

For Quick Info

Name

Mobile

E-mail

City

Class

Vertical Limit

Top Contributors

All Time This Month Last Week

Bipin Dubey

Altitude -	16545 m
Post -	7958

Himanshu

Altitude -	10925 m
Post -	3836

Hari Shankar

Altitude -	9960 m
Post -	2185

edison

Altitude -	10815 m
Post -	7797

Sagar Saxena

Altitude -	8625 m
Post -	8064

Yagyadutt Mishr..

Altitude -	6330 m
Post -	1979

Find Posts by Topics

Physics

Topics

10273

20999

3868

2300

8075

2968

2792

Mathematics

Chemistry

Biology

Institutes

Parents Corner

Board

Fun Zone

35,229,755
Engineering Questions Attempted

6,69,530
Visitors Monthly

79
Engg. Exam Covered

285
Students Currently Online

Connect with Us

Vriti Communities