|

Analytical Geometry

New kid on the Block

 Joined: 11 Jun 2012 Post: 2
11 Jun 2012 14:32:16 IST
0 People liked this
1
327
find the point on x axis equidistant from (7,6) and (-3,4)
Engineering Entrance , JEE Main , JEE Advanced , Mathematics , Analytical Geometry

find the point on x axis equidistant from (7,6) and (-3,4)

Blazing goIITian

Joined: 1 Apr 2007
Posts: 4025
11 Jun 2012 17:13:00 IST
0 people liked this

assume any point on x axis say (x,0)........

this point is equidistant from given points that means............((x-7)(square)+(0-6)(square))root=((x+3)(square)+(0-4)(square))root

on solving....x(square)+49-14x+36=x(sq)+9+6x+16.........

equating,,,,,,,85-25=20x

60=20x

x=3........so (3,0) is the requiredpoint..............

 Some HTML allowed. Keep your comments above the belt or risk having them deleted. Signup for a avatar to have your pictures show up by your comment If Members see a thread that violates the Posting Rules, bring it to the attention of the Moderator Team

## For Quick Info

Name

Mobile

E-mail

City

Class

Vertical Limit

Top Contributors
All Time This Month Last Week
1. Bipin Dubey
 Altitude - 16545 m Post - 7958
2. Himanshu
 Altitude - 10925 m Post - 3836
3. Hari Shankar
 Altitude - 9960 m Post - 2185
4. edison
 Altitude - 10815 m Post - 7797
5. Sagar Saxena
 Altitude - 8625 m Post - 8064
 Altitude - 6330 m Post - 1979

Physics

Topics

Mathematics

Chemistry

Biology

Institutes

Parents Corner

Board

Fun Zone