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Analytical Geometry

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13 Nov 2009 12:47:16 IST

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Hello friends!!!!!! One interesting question for you all!

None

This question is wrong and meaningless and has nothing to do with your courses and entrance exam...but was seems to be interesting..................

As we know that two perpendicular lines has product of slope equal to -1.

Like suppose y=m1x and y=m2 x is two perpendicular line...........

Then m1.m2 = -1.

...............then y=0 and x=0 these two line are also perpendicular......but here we have not this condition.....of m1.m2=-1...............here we have m1.m2 =0..............

So is y=0 and x=0 are not perpendicular.............or m1.m2 = -1 is wrong............or still you can prove that.....slope of y=0 and x=0 has product = -1.

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Comments (7)

Vivek Roy

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13 Nov 2009 12:58:53 IST

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the slope of the line y=0 is 0 but the slope of the line x=0 is infinity......... Now u will atgue that infinity*0 is equal to zero....... It is not.. zero multiplied by an finite quantity will give you zero, but not with any infinite number.... infinity multiplied by zero is a finite quantity whose value is arbitrarily assigned to match with the problem......

Dasvidaniya

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13 Nov 2009 13:05:25 IST

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really funnier...:-) ........(slope of y-axis) (slope of x-axis) = -1 means .........(.infinity )( zero) = -1... yeah yagya.......

Yagyadutt Mishra

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13 Nov 2009 13:24:13 IST

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No body else is interested in question.!!!!!!!!!!!!!!!!!!!

umesh

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13 Nov 2009 13:27:07 IST

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very good question

lets start from fundamental where did you drive that m1 m2=-1

lets start proof

lets y=m1x+c1,y=m2x+c2 are two lines

to find angle between them say theta

tan theta =tan(theta1-theta2)= (tan (theta1) -tan (theta2))/(1+tan (theta1)tan (theta2))

for lines to be perpendiculars

tan theta should be infinity

means (1+tan (theta1)tan (theta2)) =0

1+m1m2=0

proved

now coming back to your question

y = c and x =b are two lines

m1 = 0 and m2 = infinity in the very first equation you wil get the result

Yagyadutt Mishra

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13 Nov 2009 14:55:28 IST

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DEVENDRA MEHENDALE

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24 Jan 2010 20:11:42 IST

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CAN IT BE DONE USING PRODUCT OF TWO LINES(PAIR OFSTRAIGHT LINES) AND THUS tan (theta) =

Aman Kumar Srivastava

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Joined: 22 Aug 2010

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9 Sep 2010 07:25:24 IST

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E: x²/a²+y²/b²=1 and C: x²+y²+2gx+2fy+c=0

then equation E+lemda C=0 represent a curve which passess through the comman point of the ellipse and circle..

Qus-The Center of circle C which passess throuch the three points on E whose eccentric angles are Alpha,Beta,Gamma.....

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