Home » Ask & Discuss » Mathematics. » Analytical Geometry « Back to Discussion



Analytical Geometry

vibhor gupta's Avatar
Hot goIITian

Joined: 3 Oct 2009
Post: 129
15 Oct 2009 20:08:42 IST
0 People liked this
5
506 View Post
Q 1 :Find the locus of the middle points of the intercepts made by the axes on the lines drawn t
None

Q 1 :Find the locus of the middle points of the intercepts made by the axes on the lines drawn thru the pt(a,b)

 

Q2 : A line forms a ∆ of area 54√3 sq unts wid d coordinate axis.find the eqn of the line if the perpendicular drawn frm the origin makes an angle of 60 wid the + x axisQ3 :In a ∆ABC d(20,25) & e(8,16) are the foot of perpendicular frm A & B to the opp. sides . if c(10,15) find the orthocentre.


Share this article on:

Comments (5)

Bipin Dubey's Avatar

Forum Expert
Joined: 23 Jan 2007
Posts: 7942
15 Oct 2009 20:15:44 IST
2 people liked this

Let the line intersects axes at (p,0) and (0,q)

 

equation of line :  x/p + y/q = 1

 

since (a,b) passes through the line :  a/p + b/q = 1

 

mid point of (p,0) and (0,q) is (p/2,q/2) = (h,k) let    =>    p-2h, q=2k

 

so, a/2h + b/2k = 1

 

locus of (h,k) is a/x + b/y = 2    =>    ay+bx = 2xy

 

 

Nikhil Gupta's Avatar

Scorching goIITian

Joined: 23 Oct 2007
Posts: 279
15 Oct 2009 22:49:01 IST
0 people liked this

Sol 2---

Let the length of perpendicular drawn from the origin to the line be p...

Then    a = p/cos60

             b = p/sin60      (where a and b are x- and y- axis intercepts respectively)

Now

 

Ar(triangle) = 54√3  = 1/2 *base*height = 1/2 * (p/sin60)*(p/cos60)

     =>  p = 9

=> a= 18/√3   and b= 18

Hence eqn of line is   x/18√3  + y/ 18 = 1

Tell me if i'm right or not

vibhor gupta's Avatar

Hot goIITian

Joined: 3 Oct 2009
Posts: 129
15 Oct 2009 23:24:22 IST
0 people liked this

no nikhhil i m nt satisfied
kabi's Avatar

Blazing goIITian

Joined: 11 Jan 2009
Posts: 575
16 Oct 2009 00:23:09 IST
1 people liked this

hello

we have D ( 20,25) E ( 8,16) C( 10,15 )

slope of AC = -1/2

slope of BC = 1

Thus slope of BE = 2 and that of AD = -1

thus the eq. of AD becomes y +x = 45

eq. of BE  is y = 2x

the point of concurrency is x = 15 y=30 ie. coordinate of orthocenter .

thank u sorry if there is a calculation mistake as i m solving in hurry . 

one more thing the approach used by the student who have given the second answer is correct . 

ankur gupta's Avatar

Scorching goIITian

Joined: 10 Mar 2007
Posts: 257
23 Oct 2009 22:19:20 IST
1 people liked this

2) i m just correcting nikhil's sol....

nikhil method is correct till p=9

now , a = p/cos60 = 18and b= p/sin60 = 18/sqrt(3)

so, the equation of line is

x/18 + ysqrt(3)/18 =1

x + ysqrt(3) = 18

hope u gt it .....in case of ny problem tl me...




Quick Reply


Reply

Some HTML allowed.
Keep your comments above the belt or risk having them deleted.
Signup for a avatar to have your pictures show up by your comment
If Members see a thread that violates the Posting Rules, bring it to the attention of the Moderator Team
Free Sign Up!

Preparing for IIT-JEE ?

Arihant Revision Package for IIT JEE - Books, Practice Tests + Rank Predictor


@ INR 1,995/-

For Quick Info

Name

Mobile No.

Find Posts by Topics

Physics.

Topics

Mathematics.

Chemistry.

Biology

Parents

Board

Fun Zone

Sponsored Ads