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Analytical Geometry

Blazing goIITian

 Joined: 10 Oct 2011 Post: 434
6 Jul 2012 13:27:02 IST
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The area of the quadrilateral formed by y=1-x, y=2-x and the coordinate axes is
Engineering Entrance , JEE Main , JEE Main & Advanced , Mathematics , Analytical Geometry

The area of the quadrilateral formed by y=1-x, y=2-x and the coordinate axes is

Blazing goIITian

Joined: 8 Oct 2008
Posts: 8064
6 Jul 2012 21:47:31 IST
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hello

a trapezium of height 1/root2

and parallel side of root2 and 2*root2 would be formed:-

area=1.5

Blazing goIITian

Joined: 10 Oct 2011
Posts: 434
6 Jul 2012 22:38:48 IST
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how a parallel side of root2 and 2*root2 would be formed??plz tell

Blazing goIITian

Joined: 10 Oct 2011
Posts: 434
11 Jul 2012 11:49:22 IST
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plz tell

Blazing goIITian

Joined: 26 May 2010
Posts: 1362
11 Jul 2012 11:58:36 IST
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is the anwer mentioned by bhaiya is correct coz m too getting 3/2 or 1.5???

Blazing goIITian

Joined: 26 May 2010
Posts: 1362
11 Jul 2012 12:04:55 IST
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Blazing goIITian

Joined: 10 Oct 2011
Posts: 434
11 Jul 2012 12:32:47 IST
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yes the ans. is correct

Blazing goIITian

Joined: 26 May 2010
Posts: 1362
11 Jul 2012 12:39:43 IST
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see for finding that root 2 ,use the concept of distance between two parallel lines formula....as the lines are parallel ....and then for that 2/root 2 ...find the length of the hypotenuse for the second line---y=2-x and then subtract from it the lenght of the base of the rectangle (as u divide the trapezium in 2 right triangle and one rectabgle) which is equal to root 2 the length of the hypotenuse of the right triangle formed byu the first line....y=1-x!

Blazing goIITian

Joined: 10 Oct 2011
Posts: 434
11 Jul 2012 13:33:58 IST
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thnxx

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