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Botany
1) Trihybrid ratio is
a) 27:9:9:9:3:3:3:1
b) 27:9:9:6:6:3:3:1
c) 1:6:15:20:15:6:1
d) 36:6:6:6:3:3:3:1
2) Ratio between completely homozygous dominant and homozygous recessive individuals of dihybrid cross is
a) 1:1
b) 2:2
c) 6:10
d) 10:6
3) A dihybrid cross is made between YYrr and yyRR. In F2 generation the ratio of parental to recombinant phenotype is
a) 75%
b) 50%
c) 25%
d) 12.5%
4) A Yellow round seeded Pea plant is crossed with green wrinkled seeded Pea plant. Four phenotypes appeared in the progeny in the ratio of 1:1:1:1.The genotype of the two ratio are
a) YyRr
b) YYRR
c) YyRR
d) yyRr
PLEASE ANSWER WITH SOLUTION.
THANKS IN ADVANCE.
Comments (3)

Q1) explaination
in a dihybrid cross we get ratio 9:3:3:1 by multiplying (3:1)(3:1) coz independent charecters segregate independent of each other(law of independent assortment) likewise u cn get the reqd ratio by multiplying (3:1)(3:1)(3:1) => (9:3:3:1)(3:1) =>27:9:9:9:3:3:3:1











