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anu anu's Avatar
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20 Jan 2009 21:42:21 IST
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PLease.... solve
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1) Trihybrid ratio is

a) 27:9:9:9:3:3:3:1

b) 27:9:9:6:6:3:3:1

c) 1:6:15:20:15:6:1

d) 36:6:6:6:3:3:3:1

 

2) Ratio between completely homozygous dominant and homozygous recessive individuals of dihybrid cross is

a) 1:1

b) 2:2

c) 6:10

d) 10:6

 

3) A dihybrid cross is made between YYrr and yyRR. In F2 generation the ratio of parental to recombinant phenotype is

a) 75%

b) 50%

c) 25%

d) 12.5%

 

4) A Yellow round seeded Pea plant is crossed with green wrinkled seeded Pea plant. Four phenotypes appeared in the progeny in the ratio of 1:1:1:1.The genotype of the two ratio are

a) YyRr

b) YYRR

c) YyRR

d) yyRr

 

PLEASE ANSWER WITH SOLUTION.

 

THANKS IN ADVANCE.


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Comments (3)

Sahithya's Avatar

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Joined: 3 Sep 2008
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21 Jan 2009 13:07:26 IST
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1 a 27:9:9:9:3:3:3:1
victor's Avatar

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22 Jan 2009 11:28:07 IST
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for 1st.. a) 27:9:9:9:3:3:3:1 , for 2nd) 1:1 ( only one AABB and aabb), 3rd ) F1 = YyRr , parental phenotypes in F2 = Y_rr + yyR_ where in _ , you can fill either dominant or recessive allele... it will be 6/16 in total i.e there will be 6 parental phenotypes.. recombinant will be 10 out of 16..so, ratio comes out to be near 60% for 4th) answer is YyRr .. then only can the ratio 1:1:1:1 obtained..
Honey Arora's Avatar

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22 Jan 2009 22:48:00 IST
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Q1) explaination

in a dihybrid cross we get ratio 9:3:3:1 by multiplying (3:1)(3:1) coz independent charecters segregate independent of each other(law of independent assortment) likewise u cn get the reqd ratio by multiplying (3:1)(3:1)(3:1) => (9:3:3:1)(3:1) =>27:9:9:9:3:3:3:1




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