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  DIVISIBILITY TESTS   7 Nickels awarded!
Tagged with:    [Post New]posted on 1 Aug 2008 09:40:39 IST    

Friends I will prove all the divisibility.


I know you know all of them but just for those who don't know can see this.


Let the number be x=a_ma_{m-1}a_{m-2}..............a_2a_1a_0


As a0 is the unit digit of the number then  the number can be written as x=a_0+10a_1+10^2a_2....................10^ma_m


 


 


DIVISIBILITY TEST FOR 2.


A number is divisible by 2 if the last digit is divisible by 2.


We know 10\equiv0\ mod\ 2


And x=a_0+10a_1+10^2a_2....................10^ma_m


So x\equiv a_0+0a_1+0^2a_2....................0^ma_m\ mod\ 2


\Rightarrow x \equiv a_0\ mod\ 2


Hence a number is divisible by 2 if the last digit is divisible by 2.


 


DIVISIBILITY TEST FOR 3.


A number is divisible by 3 if the sum of the digits is divisible by 3.


10\equiv1\ mod\ 3


And x=a_0+10a_1+10^2a_2....................10^ma_m


So x\equiv a_0+1a_1+1^2a_2....................1^ma_m\ mod 3


\Rightarrow x\equiv a_0+a_1+a_2....................a_m\ mod\ 3


Hence A number is divisible by 3 if the sum of the digits is divisible by 3.


 


 


DIVISIBILITY TEST FOR 4


A number is divisible by 4 if the last two digits are divisible by 4.


100\equiv0\ mod\ 4


And x=a_0+10a_1+10^2a_2....................10^ma_m


So x\equiv a_0+10a_1+0a_2....................0a_m\ mod\ 4


\Rightarrow x\equiv a_0+10a_1\ mod\ 4


Hence A number is divisible by 4 if the last two digits are divisible by 4.


 


DIVISIBILITY TEST FOR 5.


A number is divisible by 5 if the last digit is divisible by 5.


We know that 10\equiv0\ mod\ 5


And x=a_0+10a_1+10^2a_2....................10^ma_m


So x\equiv a_0+0a_1+0^2a_2....................0^ma_m\ mod\ 5


\Rightarrow x\equiv a_0\ mod\ 5


Hence a number is divisible by 5 if the last digit is divisible by 5.


 


DIVISIBILITY TEST FOR 9.


A number is divisible by 9 if the sum of the digits is divisible by 9.


10\equiv1\ mod\ 9


And x=a_0+10a_1+10^2a_2....................10^ma_m


So x\equiv a_0+1a_1+1^2a_2....................1^ma_m\ mod\ 9


\Rightarrow x\equiv a_0+a_1+a_2....................a_m\ mod\ 9


Hence A number is divisible by 9 if the sum of the digits is divisible by 9.


 


DIVISIBILITY TEST FOR 10


10\equiv0\ mod\ 10


And x=a_0+10a_1+10^2a_2....................10^ma_m


So x\equiv a_0+0a_1+0^2a_2....................0^ma_m\ mod\ 10


\Rightarrow x\equiv a_0\ mod\ 10


Hence a number is divisible by 10 if the last digit is divisible by 10.


 


DIVISIBILITY TEST FOR 11


10\equiv-1\ mod\ 11


And x=a_0+10a_1+10^2a_2....................10^ma_m


So x\equiv a_0+(-1)a_1+(-1)^2a_2....................(-1)^ma_m\ mod\ 11


\Rightarrow x\equiv a_0-a_1+a_2....................(-1)^ma_m\mod\ 11


 


 


I took a lot of time typing it and in the TEXER.


If it have helped then please leave a commentand rate if you liked it.

About the Author:
rudra.panda (2802)

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Olaaa!! Perrrfect answer. 480  [681 rates]

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sahilmadaan12
sahilmadaan12 is offline comment by sahilmadaan12    (posted on 1 Aug 2008 10:19:17 IST)
good one!!
GoNik
GoNik is offline comment by GoNik    (posted on 1 Aug 2008 11:13:26 IST)
nice rey!!!!!!
Protyush_Sahu
Protyush_Sahu is offline comment by Protyush_Sahu    (posted on 1 Aug 2008 13:28:27 IST)
wonderful
vibhu.oct
vibhu.oct is offline comment by vibhu.oct    (posted on 1 Aug 2008 22:46:47 IST)
marvellous
knowmonger
knowmonger is offline comment by knowmonger    (posted on 1 Aug 2008 23:16:42 IST)
Nice. Food for thought.
krish1092 is offline comment by krish1092    (posted on 2 Aug 2008 18:25:44 IST)
nice work
smilingbharat
smilingbharat is offline comment by smilingbharat    (posted on 2 Aug 2008 19:46:27 IST)
gud
rudra.panda
rudra.panda is offline comment by rudra.panda    (posted on 3 Aug 2008 10:51:54 IST)
thank you.
anay_pat is offline comment by anay_pat    (posted on 4 Aug 2008 14:17:13 IST)
very gud
shreyaarya
shreyaarya is offline comment by shreyaarya    (posted on 27 Aug 2008 20:31:19 IST)
gr88...gud work
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