for any small area dS on the sphere, net E = 0
thus E1 + E2 = 0 (in vector form)
=> |E1| = |E2|
now field lines will be almost perpendicular to dS
thrfore at dS
E A = A 
/ 
0 => E = / 0 => E1 = E2 = / 20 thrfore force on dS = dq E
=> P = F/ dS = 2 / 2 0
Back to Community Shelf
Awaiting Review for Nickels![[Post New]](/templates/default/images/icon_minipost_new.gif){kind=icon}
![[Thumb - untitled.JPG]](http://www.goiit.com/upload/2007/5/8/8a0fe846a290ec0ee47dcf97bfe5a863_478.JPG_thumb)
744
2
