E2 mechanism
In the 1920s,
Sir Christopher Ingold proposed a model to explain a peculiar type of chemical reaction: the E2 mechanism. E2 stands for
bimolecular elimination and has the following specificities.
- It is a one-step process of elimination with a single transition state.
- Typical of secondary or tertiary substituted alkyl halides. It is also observable with primary alkyl halides if a hindered base is used.
- The reaction rate, influenced by both the alkyl halide and the base, is second order.
- Because E2 mechanism results in the formation of a Pi bond, the two leaving groups (often a hydrogen and a halogen) need to be coplanar. An antiperiplanar transition state has staggered conformation with lower energy and a synperiplanar transition state is in eclipsed conformation with higher energy. The reaction mechanism involving staggered conformation is more favourable for E2 reactions.
- Reaction often present with strong base.
- In order for the pi bond to be created, the hybridization of carbons need to be lowered from sp3 to sp2.
- The C-H bond is weakened in the rate determining step and therefore the deuterium isotope effect is larger than 1.
- This reaction type has similarities with the SN2 reaction mechanism.
Saturated (sp3-hybridized) carbons will not react as readily with E2 and it will with E1 due to the steric hindrince. If SN1 and E1 are competing for the reaction, the E2 can be achieved by increasing the heat.
The reaction fundamental elements are
- Breaking of the carbon-hydrogen and carbon-halogen bonds in one step.
- Formation of a carbon=carbon Pi bond.
E1 mechanism
E1 is a model to explain a particular type of chemical elimination reaction. E1 stands for unimolecular elimination and has the following specificities.
- It is a two-step process of elimination ionization and deprotonation.
- Typical of tertiary and some secondary substituted alkyl halides.
- The reaction rate is influenced only by the concentration of the alkyl halide because carbocation formation is the slowest, rate-determining step. Therefore first order kinetics apply.
- Reaction mostly occurs in complete absence of base or presence of only weak base.
- E1 reactions are in competition with SN1 reactions because they share a common carbocationic intermediate.
- Deuterium isotope effect is absent.
- accompanied by carbocationic rearrangement reactions
An example in scheme 2 is the reaction of tert-butylbromide with potassium ethoxide in ethanol.
E1 eliminations happen with highly substituted alkyl halides due to 2 main reasons.
- Highly substituted alkyl halides are bulky, limiting the room for the E2 one-step mechanism; therefore, the two-step E1 mechanism is favored.
- Highly substituted carbocations are more stable than methyl or primary substituted. Such stability gives time for the two-step E1 mechanism to occur.
E2 and E1 elimination final notes
The
reaction rate is influenced by
halogens reactivity;
iodide and
bromide being favored. Fluoride is too reactive and its level of
basicity too high. There is a certain level of competition between
elimination reaction and
nucleophilic substitution. More precisely, there are competitions between E2 and
SN2 and also between E1 and
SN1. Substitution generally predominates and elimination occurs only during precise circumstances. Generally, elimination is favored over substitution when
In one study
[1] the
kinetic isotope effect (KIE) was determined for the gas phase reaction of several alkyl halides with the
chlorate ion. In accordance with a E2 elimination the reaction with
t-butyl chloride results in a KIE of 2.3. The
methyl chloride reaction (only S
N2 possible) on the other hand has a KIE of 0.85 consistent with a S
N2 reaction because in this reaction type the C-H bonds tighten in the transition state. The KIE's for the ethyl (0.99) and isopropyl (1.72) analogues suggest competition between the two reaction modes.
Specific elimination reactions
NOT SELF written......................
found it useful
hope u like that