Community Contributions - Articles by goIITians
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| First and Second order diff equa..... |
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posted on 3 Feb 2008 19:34:09 IST
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First Order Differential equations A first order differential equation is of the form: -
Linear Equations: The general general solution is given by where is called the integrating factor.
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Separable Equations: - (1)
- Solve the equation g(y) = 0 which gives the constant solutions.
- (2)
- The non-constant solutions are given by
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Bernoulli Equations: - (1)
- Consider the new function
. - (2)
- The new equation satisfied by v is
- (3)
- Solve the new linear equation to find v.
- (4)
- Back to the old function y through the substitution
. - (5)
- If n > 1, add the solution y=0 to the ones you got in (4).
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Homogenous Equations: is homogeneous if the function f(x,y) is homogeneous, that is By substitution, we consider the new function The new differential equation satisfied by z is which is a separable equation. The solutions are the constant ones f(1,z) - z =0 and the non-constant ones given by Do not forget to go back to the old function y = xz. -
Exact Equations: is exact if The condition of exactness insures the existence of a function F(x,y) such that All the solutions are given by the implicit equation Second Order Differential equations -
Homogeneous Linear Equations with constant coefficients: Write down the characteristic equation - (1)
- If
and are distinct real numbers (this happens if ), then the general solution is - (2)
- If
(which happens if ), then the general solution is - (3)
- If
and are complex numbers (which happens if ), then the general solution is where that is -
Non Homogeneous Linear Equations: The general solution is given by where  is a particular solution and  is the general solution of the associated homogeneous equation In order to find  two major techniques were developed. -
Method of undetermined coefficients or Guessing MethodThis method works for the equation where a, b, and c are constant and where  is a polynomial function with degree n. In this case, we have where The constants  and  have to be determined. The power s is equal to 0 if  is not a root of the characteristic equation. If  is a simple root, then s=1 and s=2 if it is a double root. Remark. If the nonhomogeneous term g( x) satisfies the following where  are of the forms cited above, then we split the original equation into N equations then find a particular solution  . A particular solution to the original equation is given by -
Method of Variation of Parameters This method works as long as we know two linearly independent solutions of the homogeneous equation Note that this method works regardless if the coefficients are constant or not. a particular solution as where  and  are functions. From this, the method got its name. The functions  and  are solutions to the system: which implies Therefore, we have -
Euler-Cauchy Equations: where b and c are constant numbers. By substitution, set then the new equation satisfied by y(t) is which is a second order differential equation with constant coefficients. - (1)
- Write down the characteristic equation
- (2)
- If the roots
and are distinct real numbers, then the general solution is given by - (2)
- If the roots
and are equal ( ), then the general solution is - (3)
- If the roots
and are complex numbers, then the general solution is where and . It is definitely pasted from a site.....but thought pasting it is quite meaningfull and helpfull..... pls do comment........
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this article: 76 points
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(posted on 3 Feb 2008 19:37:05 IST)
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| gud work yaar........... |
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(posted on 4 Feb 2008 14:40:34 IST)
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42 views but no comments!!!!!!!!!!
haa its shocking......... |
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(posted on 4 Feb 2008 23:53:50 IST)
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u must be thank ful that it is viewed and be sure when not very many comeeents, then it is obviously goiit friendly..... matlab always comments do not decide the article of ur value,,,,, nyways ur attempt is good,,,, thanks 4 helping me + 42 to revise,,,, 43 thanks from my side,,,,, just chidding yarrrr |
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(posted on 6 Feb 2008 10:45:54 IST)
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gud hai :| keep it up... |
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(posted on 6 Feb 2008 10:57:30 IST)
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its gud tht u have sum up thngs........ i will bokmark it, cos ya i needed the formulas to be with me during exaam time.. there r some uncommon form. also thanx 4 those |
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(posted on 6 Feb 2008 11:05:23 IST)
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Nice work......mate .........cmon post in some more......I beleive u hv more than just this in your "Brain bank" ......... Cheers !!!!!!!!!!!!!!!! :):):):):) |
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(posted on 6 Feb 2008 12:14:42 IST)
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nice work
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(posted on 6 Feb 2008 14:02:26 IST)
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thank u for summarizing it yaar i really needed sumthing like this
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(posted on 6 Feb 2008 16:14:36 IST)
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| gud job!!!!!!!!!!!!!! |
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(posted on 6 Feb 2008 23:19:22 IST)
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| niclyyyy explaineddd...... |
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(posted on 6 Feb 2008 23:19:51 IST)
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| niclyyyy explaineddd...... |
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(posted on 6 Feb 2008 23:23:02 IST)
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| gud work... |
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(posted on 7 Feb 2008 21:08:30 IST)
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hey!! well explained! keep up the gud work!! :)
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(posted on 19 Feb 2008 12:06:08 IST)
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| perfect it is what i needed thanks |
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