integration

Blazing goIITian

Posted on
15 Jan 2008 22:28:37 IST
Posts: 2537
15 Jan 2008 22:28:37 IST
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integration


There is a general method to find integration of sin 9x / sin x , sin 11x/ sin x etc.

we know,
[ ][ ] sinx dx / sin x  = x + C

[ ][ ] sin 3x dx / sin x  = x + sin 2x + C

[ ][ ] sin 5x dx / sin x  = x + sin 2x + sin 4x / 4 + C

therefore,
[ ][ ] sin 7x dx / sin x =  x + sin 2x + sin 4x / 2  +  sin 6x / 3 + C

in this method, we can find integration of sin 9x / sin x , sin 11x/ sin x etc.

( courtesy : Chakrapani Dutta, my friend )

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Comments (2)


Hot goIITian

Joined: 27 Aug 2007 14:35:10 IST
Posts: 112
15 Jan 2008 23:03:22 IST
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great!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Blazing goIITian

Joined: 22 Apr 2007 11:21:45 IST
Posts: 2537
19 Jan 2008 22:01:43 IST
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again chakrapani dutta did wonder , though with a bit of my help this time

pattern of indefinite integration for sin 2nx/ sin x

sin 2x/ sin x = 2 [ sin x] + C

sin 4x/ sin x = 2[ sin x + (sin 3x) / 3 ] + c

sin 6x/ sin x = 2[ sin x + (sin 3x) / 3 + (sin 5x) / 5] + c

in this way we can integrate even sin10x/sinx, sin 12x/sinx, etc. the value of

sin 10x/ sin x = 2[ sin x + (sin 3x) / 3 + (sin 5x) / 5 + (sin 7x) / 7 + (sin9x) / 9] + c




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