INTEGRATION TO BEGIN WITH
u dv = uv -
v du
x3 dx/(1 + x4 ) in this Q we substitute 1+x4 = t
x3 dx/(1 + x4 ) =
dt/t = log t + c = log(1 + x4) + c
(a2 - x2) dx = (x/2)(
(a2 - x2) + (a2/2)sin-1(x/a) + c
(x2 - a2) dx = (x/2)(
(x2 - a2) - (a2/2)log[x +
(x2 - a2)] + c
(x2 + a2) dx = (x/2)(
(x2 + a2) + (a2/2)log[x +
(x2 + a2)] + c
dx/[
(a2 - x2) = sin-1(x/a) +c
dx/[
(x2 - a2) = log[x+
(x2 - a2)] + c
dx/[
(x2 + a2) = log[x+
(x2 + a2)] + c
dx/(a2 - x2) = (1/2a)log [ (a+x)/(a-x)] + c
dx/(x2 - a2) = (1/2a)log [ (x-a)/(x+a)] + c
dx/(x2 + a2) = (1/a)tan-1(x/a) + c
(eax sin bx ) dx = [eax/a2 + b2][a sinbx - bcosbx] + c
axdx = ax/logea + c
f '(x)/f(x) dx = log[f(x)] + c
f ' (x) /
f(x) dx = 2 *
f(x) + c
Comments (4)











