points for solving numericals based upon krichoff's law :-

 

1)Give the naming to the corners and junctions of the circuit ( here ABCDEF )

 

2)Distribute current in a circuit using K.F.Law starting preferrably frm battery outside the circuit ( here E1 is most outside.)

 

3)Choose a close loop , if on moving the finger along the loop , the finger goes along the direction of current , current is taken as  +ive , however if the finger move opposite to the direction of the current , the current is taken as -ive

 

4)On moving the finger along the loop , if the finger goes frm +ive to -ive pole , EMF is -ive , However if the finger moves frm -ive pole to +ive pole , EMF is taken as +ive

 

 

here...

 

frm closed loop BCFB

 

I₁R₂ + I₂R₃ - ( I - I₁) R₅ = E₂ - E₃

 

frm closed loop CDFC

 

(I₁ - I₂) R₄ - ( I - I₁ + I₂ ) R₆ - I₂R₃ = -E₄ + E₃

 

for closed loop ABFDEA

 

(I - I₁) R₅ + ( I - I₁ + I₂) R₆ + IR₁ = + E

 

 

hence by these 3 equations , we can find I , I₁ & I₂