Given any 2 digit number that ends in 5, and it can b squared in the head!
452 = 2025
852 = 7225, etc.
There's a quick way to do this: if the first digit is N and the second digit is 5, then the last 2 digits of the answer will be 25, and the preceding digits will be N*(N+1).
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SUMk=1 to infinity ( 1/k2 ) = ( Pi2/6 )
SUMk=1 to infinity ( 1/k4 ) = ( Pi4/90 )
SUMk=1 to infinity ( 1/k6 ) = ( Pi6/945 )
SUMk=1 to infinity ( 1/k8 ) = ( Pi8/9450 )
SUMk=1 to infinity ( 1/k10 ) = ( Pi10/93,555 )