Now, lets see one more application of the formulas developed in the previous article.
Most of you must have come across the problem
Two projectiles have the same range R and heights H
1 & H
2 . Prove that
R = 4

H
1H
2 Those of you who haven't solved this before try to do it. After you have broken your heads, or managed to solve it, come and see this solution.
As the ranges are same, they are projected at say,

and 90 -

4H
1 = Rtan

4H
2 = Rtan(90-

) => 4H
2 = Rcot

then,
16H
1H
2 = R
2 
R = 4

H
1H
2