Projectiles continued

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19 May 2007 10:19:40 IST
Posts: 1777
19 May 2007 10:19:40 IST
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Projectiles continued

Now, lets see one more application of the formulas developed in the previous article.
Most of you must have come across the problem
Two projectiles have the same range R and heights H1 & H2 . Prove that
R = 4 H1H2
Those of you who haven't solved this before try to do it. After you have broken your heads, or managed to solve it, come and see this solution.
As the ranges are same, they are projected at say, and 90 -
4H1 = Rtan
4H2 = Rtan(90-) => 4H2 = Rcot
then,
16H1H2 = R2
R = 4 H1H2

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Comments (2)


Blazing goIITian

Joined: 1 Jan 2007 13:08:15 IST
Posts: 501
19 May 2007 17:59:15 IST
0 people liked this

yaar some symbols r missing in d formulae

Hot goIITian

Joined: 29 Oct 2007 02:27:48 IST
Posts: 173
10 Jan 2008 01:56:46 IST
0 people liked this

same question as mentioned above



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