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  Proof of the Fundamental Theorem of Calculus...............dont miss it.   2 Nickels awarded!
Tagged with:    [Post New]posted on 6 Aug 2008 23:46:02 IST    


Fundamental Theorem of Calculus











If f is the derivative of F, then

ób

ô

õ
a


f(x) dx = F(b) - F(a)


Before we prove the Fundamental Theorem of Calculus, let's define a few terms...


Riemann Sum



(Georg Friedrich Bernhard Riemann (1826-1866) was most famous for work in non-Euclidean geometry, differential equations, and number theory.  His results in physics and mathematics form the basis of Einstein's theory of general relativity.)



Let f be defined on [a,b], and let D be a partition of [a,b] given by



a = x0 < x1 < x2 < ... < xn-1 < xn = b



where Dxi is the length of the ith subinterval.  If ci is any point in the ith sub-interval then the sum











n

S

i=1


f(ci) Dxi,   xi-1 <= ci <= xi


is called a Riemann sum of f for the partition D.


The limit as the length of the largest subinterval of partition D (the norm of the partition, denoted IIDII) approaches zero (if it exists) is the definite integral, denoted











ób

ô

õ
a


f(x) dx


Proof of the Fundamental Theorem of Calculus











If f is the derivative of F, then

ób

ô

õ
a


f(x) dx = F(b) - F(a)


Let D be a partition of [a,b] with



a = x0 < x1 < x2 < ... < xn-1 < xn = b



Using this partition, F(b)-F(a) can be rewritten as











n

S

i=1


( F(xi) - F(xi-1) )


By the Mean Value Theorem, there exists a number in each subinterval (call it ci) such that



F'(ci) = (F(xi) - F(xi-1)) / (xi - xi-1)



Because F' is f, F'(ci) = f(ci).  We let Dxi = xi - xi-1 , which means we can rewrite the sum, above, as











F(b) - F(a) = 

n

S

i=1


f(ci) Dxi


Taking the limit as IIDII --> 0,











F(b) - F(a) = 

ób

ô

õ
a


f(x) dx

About the Author:
reddevil_2009 (1410)

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Olaaa!! Perrrfect answer. 244  [339 rates]

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reddevil_2009
reddevil_2009 is offline comment by reddevil_2009    (posted on 6 Aug 2008 23:49:26 IST)
sorrrry for poor editing............but plzzzzz comment
kria
kria is offline comment by kria    (posted on 7 Aug 2008 13:07:30 IST)
NICE..
tgt_2k9
tgt_2k9 is offline comment by tgt_2k9    (posted on 25 Aug 2008 00:29:56 IST)
gr8888888888 job
knowmonger
knowmonger is offline comment by knowmonger    (posted on 25 Aug 2008 21:19:30 IST)
Dude, I wud appreciate proper formatting.
prashant_prakhar
prashant_prakhar is offline comment by prashant_prakhar    (posted on 25 Aug 2008 22:01:36 IST)
arrange it properly yaar
challnger_10 is offline comment by challnger_10    (posted on 24 Sep 2008 00:19:48 IST)
good
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