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Tagged with:    [Post New]posted on 10 Aug 2007 09:11:39 IST    
Here are some of the most basic graphs, and the effects of making changes to the basic definitions of the functions:
Line:  y=x Parabola:  y=x2 Cubic:  y=x3
Change sign of coefficient:
y = -x
Change sign of coefficient:
y = -x2
Change sign of coefficient:
y = -x3
Change to Slope:  y=2x
Change to Horizontal Component: 
 y = (x + 1)2
Change to Horizontal Component:
y = (x-2)3
Change to vertical component:
y = x + 3
Change to Vertical Component:
y = x2 - 4
Change to Vertical Component:
Y = x3 + 4

OTHER  BASIC  GRAPHS
y = |x| y = ex y = 1/x
NOW FOR PART 2.................


Problem: Graph the following system:
2x + y >= 2
4x + 3y <= 12
(1/2) <= x <= 2
y >= 0


Solution:
See the figure below.
Inequality Solution Figure



Problem: Graph y < x.

Solution:
First graph the equation y = x.
However, the line must be drawn dashed
because the less than sign tells us the
line is not included in the
solution.
Next, test a point that is located above
the line and one that is below the line.
Any point you pick above the line, such
as (0, 2), y is greater than x,
so points above the line are not in-
cluded in the solution. Points below the
line, such as (3, -3) have a y
value that is less than the x
value, so all points below the line are

included in the solution.
Inequality Graph Example





SKETCHING THE GRAPH OF RATIONAL FUNCTIONS............!!!!!!!!!!!



Definition
A rational function f has the form
f(x)=g(x)/h(x)
where g (x) and h (x) are polynomial functions.
The domain of f is the set of all real numbers except the values of x that make the denominator h (x) zero.
In what follows, we assume that g (x) and h (x) have no common factors.
Vertical Asymptotes
Let
f(x)=2/(x-3)
The domain of f is the set of all real numbers except 3, since 3 makes the denominator zero and the division by zero is not allowed in mathematics. However we can try to find out how does the graph of f behave close to 3.
let us evaluate function f at values of x close to 3 such that x < 3. The values are shown in the table below:
x 1 2 2.5 2.8 2.9 2.99 2.999 2.99999
f (x) -1 -2 -4 -10 -20 -200 -2000 -2*105
Let us now evaluate f at values of x close to 3 such that x > 3.
x 5 4 3.5 3.2 3.1 3.01 3.001 3.00001
f (x) 1 2 4 10 20 200 2000 2*105
The graph of f is shown below.
vertical asymptote
Notes
1 - As x approaches 3 from the left or by values smaller than 3, f (x) decreases without bound.
2 - As x approaches 3 from the right or by values larger than 3, f (x) increases without bound.
We say that the line x = 3, broken line, is the vertical asymptote for the graph of f.
In general, the line x = a is a vertical asymptote for the graph of f if f (x) either increases or decreases without bound as x approaches a from the right or from the left. This is symbolically written as:
f(x) approaches increases without bound or decreases without bound as x approaches 3

About the Author:
nivedh_89 (4512)

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Olaaa!! Perrrfect answer. 820  bad job dude!! I dont approve of this answer! 1  [1028 rates]

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nivedh_89
nivedh_89 is offline comment by nivedh_89    (posted on 10 Aug 2007 09:14:44 IST)
plzz do post ur comments whether u like it or not...........!!!!!!!!!!!!
kamalasai
kamalasai is offline comment by kamalasai    (posted on 10 Aug 2007 12:36:18 IST)
its really great........
savvej
savvej is offline comment by savvej    (posted on 10 Aug 2007 16:49:27 IST)
nice one.
rini
rini is offline comment by rini    (posted on 10 Aug 2007 16:55:08 IST)
gud!!!
coolank2
coolank2 is offline comment by coolank2    (posted on 10 Aug 2007 18:43:52 IST)
Great work man !
shivamrox123 is offline comment by shivamrox123    (posted on 10 Aug 2007 20:33:30 IST)
gr888888888888888888 job done dude
jatinroxx
jatinroxx is offline comment by jatinroxx    (posted on 10 Aug 2007 20:36:55 IST)
x= 3sin5t
y= 3cos3t is the best.......
Still wondering how dat ws traced......
nivedh_89
nivedh_89 is offline comment by nivedh_89    (posted on 10 Aug 2007 20:57:48 IST)
thnk you........!!!!!!!!!!
nivedh_89
nivedh_89 is offline comment by nivedh_89    (posted on 11 Aug 2007 11:50:14 IST)
some more comments........!!!!!!!!!!!!!!!!!!!
prathima
prathima is offline comment by prathima    (posted on 12 Aug 2007 19:50:16 IST)
veryyyyyyyyyyy nice
nivedh_89
nivedh_89 is offline comment by nivedh_89    (posted on 13 Aug 2007 10:26:33 IST)
thanxxxxxxx
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