Properties and solution of triangles :
r = 4R SinA/2.SinB/2.SinC/2
Sine rule :
a/Sina = b/Sinb = c/Sinc = 2R
Cosine rule :
CosA = b2+c2-a2/2bc
Projection rule :
a = bCosC + cCosB
Napier's rule :
tan(A-B/2) = [(a-b)/(a+b)]Cot C/2
Half angle Formulae :
Sin A/2 = [(s-b)(s-c)/bc]1/2
Cos A/2 = [s(s-a)/bc]1/2
tan A/2 = [(s-b)(s-c)/s(s-a)]1/2
Where 2s = a+b+c
Circumradius :
R = abc/4
Inradius :
r =
/s = (s-a)tan A/2
Exradius :
r0 =
/(s-a) = s tan A/2
Solution of triangles :
1)given a,b,c apply Cosine rule or half angle rule.
2)given b,c,A apply Napier's rule.
3)given a,B,C apply sine rule.
4)given b,c,B apply sine rule to obtain sinC (cases):
For acute B:
if SinC > 1
No triangle
if SinC = 1
one right angled triangle.
if SinC < 1 & cSinB < b < c
Two triangles.
if SinC < 1 & b
c
one triangle.
For Obtuse :
if b > c
one triangle.
if b
c
no triangle.
Area of triangle :

= 1/2(bcSinA) = [s(s-a)(s-b)(s-c)]
1/2
Area of cyclic quadrilateral ABCD =
[(s-a)(s-b)(s-c)(s-d)]1/2
Where 2s = a+b+c+d.
Ptolmey's theorem :
AC.BD = AB.CD + BC.AD
Area of n sided regular polygon
= nR
2/2[Sin(2

/n)]
Where R = radius of circumsircle.
= nR
2[tan(

/n)]
Hope you all find it useful.
Cheers !!!!!!!!!!!!!!!!!
