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  transformation of graphs 2   20 Nickels awarded!
Tagged with:       [Post New]posted on 2 Jul 2007 11:47:57 IST    
Case 4
To draw the graph of form y = | f(x) | (graph 4)
 
Draw the graph of y = f(x) (in yellow) then restore that part of the curve, which is above x-axis. Take the reflection of the part of the curve which is below x-axis (in yellow) wrt to x-axis. Then erase the part which is below x-axis... The restored part along with the reflection will be the required curve (in red dotted)
 
Case 5
To draw the graph of form y = f(|x|) (graph 5)
 
Draw the graph of y = f(x) (in yellow) and then erase the part which is to the left of y-axis. Take the reflection to the part of the curve lying to the right of y-axis assuming y-axis as mirror. The part of the curve, which is at the right of y-axis along with its reflection, is the required curve (in red dotted)
 
Case 6
To draw the graph of form y = f(- x) (graph 6)
 
Draw y = f(x) (in yellow)..and then take the total reflection of this graph wrt y-axis (in red)
 
Case 7
To draw the graph of form y = - f(x) (graph 7)
 
Draw y = f(x) (in yellow)..and then take the total reflection of this graph wrt x-axis (in red)




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magiclko (4205)

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Olaaa!! Perrrfect answer. 745  bad job dude!! I dont approve of this answer! 2  [989 rates]

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 this article: 20 points  (with Olaaa!! Perrrfect answer.   in 4 votes )   [?]
 
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kamalasai
kamalasai is offline comment by kamalasai    (posted on 2 Jul 2007 14:09:47 IST)
its great........
magiclko
magiclko is offline comment by magiclko    (posted on 3 Jul 2007 10:20:11 IST)
i guess no one has to comment anything on this... no probs... jus make the best possible use of it!!!
joyfrancis
joyfrancis is offline comment by joyfrancis    (posted on 3 Jul 2007 13:15:43 IST)
thanks, this would quiet a help at the time of revision.
ac
ac is offline comment by ac    (posted on 5 Jul 2007 23:50:57 IST)
Hi, you've done pretty impressive work!
AC (Forum expert, IIT Delhi alumnus).
magiclko
magiclko is offline comment by magiclko    (posted on 6 Jul 2007 12:48:09 IST)
thank u sir!
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