Vriti EdustoreZ - method to write the trend of Ionisation Energy
Hello dear friends ...After your responses ..I am submitting a new trick in chemical bonding which i had used during my exam time.....Actually question is asked only to write the trend of some selective compounds...whole periodic table is necessarily not required to mugged up....Some famous elements like N O P...are only asked...So i am submitting here a method...by which you can easily find out the trend of Ionisation energy ....
My trick in confined to these compounds only...which are mostly asked...
Li B Be C O N F
Z Z Z Z Z Z
Na Al Mg Si S P Cl
You need to remeber the way i have written.....it is not hard....because it is just the first two rows elements....except H and He ....
As we know O < N , S < P , B < Be and Al < Mg .....so i switched there position ......this is the imprtant thing in this...if you will miss this....then you will have to pay .....so my request...remeber that you have to switch the half filled orbital elements.....After that you will hit six ...
Now Question will like this.. ?
a) Write the trend of I.E of the following compound ...?
~ P , S , O , N
~ C Mg Si Be
~Be Li Na Mg
~ S Be O Mg
~Be Mg Cl F
I will solve this for you...and then will give you some question...?
You must write the all the compounds with Z drawn ....
~consider the part where....P S O N is........
How is the Z pattern......it starts from O goes to N the goes to S and then to P ...
O N
Z
S P
So just follow the line of Z with starting point at the left top tip of Z...
so Ionisation Energy trend will be O < N < S < P
~ C Mg Si Be
Consider these four in the above patterns....How is the Z structure in between....starts from Be ,, goes to C then to Mg then to Si...
So pattern will be Be < C < Mg < Si
~Be Li Na Mg
Now look in the pattern...where these four compounds are located.....it is like this....
Li B Be
Na Al Mg
when the elements are not just side by side...no problem...just focus on the four elements...remove all from the middle....
So it is simply
Li Be
Na Mg
Make a Z between them
Li Be
z
Na Mg therefore trend is Li < Be < Na < Mg
~ S Be O Mg
See where these elements are located ...
Be O Be O
(remove the middle elements consider only the four) => Z
Mg S Mg S
hence the trend is.....Be < O < Mg < S
~ Be Mg Cl F
these are located in the above pattern as ...
Be F
z
Mg Cl hence the trend is......Be < F < Mg < Cl
I have explained it step by step...thats why it will seems to be very long /....but this is quite easy than what you all actually mug up....Once you write all the elements ...it will be very easy......Just write the compound in the form they are in the table...and write Z between them ...and follow the line of Z you will get the trend....
I hope my effort is not useless for you guys...You all get my tricks or not ?
Here are few examples...which you can try...
1)Al N P B 2) Al F B Cl 3) B O S Al 4 ) Si F Cl C 5) F Cl Na Li
And don't worry....All the trend which have been asked in JEE...(past years) are only of these compounds....and they ask from this only...
Comment on the article....with your doubts..
Regards
yagya
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