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Cool goIITian

Joined:	13 Jul 2008
Post:	54

4 Oct 2008 12:18:22 IST

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734

WAP to determine whether a matrix is identity one or not?

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WAP to determine whether a matrix is identity one or not?

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Comments (5)

Sagar Saxena

Forum Expert

Joined: 8 Oct 2008

Posts: 7221

17 Oct 2008 23:26:06 IST

Like 4 people liked this

#include<stdio.h>

#include<conio.h>

void main()

{

int mat[5][5],order,i,j,flag=0;

clrscr();

printf("\n Enter a square matrix to check identity");

printf("\n\n Enter its order(n*n) ");

scanf("%d",&order);

for(i=0;i<order;i++)

{

printf("\n");

for(j=0;j<order;j++)

{

printf(" %d,%d: ",i+1,j+1);

scanf("%d",&mat[i][j]);

}

}

for(i=0;i<order;i++)

{

for(j=0;j<order;j++)

{

if(i==j)

{

if(mat[i][j]!=1)

{

flag=1;

break;

}

}

else

{

if(mat[i][j]!=0)

{

flag=1;

break;

}

}

}

}

printf("\n The given matrix is ");

if(flag==0)

printf("an identity matrix.");

else

printf("not an identity matrix.");

getch();

}

Shankhadip Majumder

Cool goIITian

Joined: 25 Apr 2008

Posts: 55

28 Oct 2008 13:27:38 IST

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if sum of all elements is no of rows or no columns and product of all left diagonal elements is equal to 1 then the matrix is an identity matrix,rate if you like the idea...

Shankhadip Majumder

Cool goIITian

Joined: 25 Apr 2008

Posts: 55

28 Oct 2008 20:31:31 IST

Like 0 people liked this

plz rate me

Shankhadip Majumder

Cool goIITian

Joined: 25 Apr 2008

Posts: 55

29 Oct 2008 20:12:52 IST

Like 1 people liked this

java (but understandable)

sum=0 s=0,p=1;

for(i=0;i<n;i++)

{

for(j=0;j<n;j++)

{if(i==j){

p=p*a[i][j];

s=s+a[i][j];}

sum=sum+a[i][j];

}

if(s==sum&&p==1)

System.out.println("IDENTITY MATRIX");

else

plz rate me

Shankhadip Majumder

Cool goIITian

Joined: 25 Apr 2008

Posts: 55

31 Oct 2008 17:38:33 IST

Like 0 people liked this

you could change.. the pgm & check whether sum of left diagonal elements is equal to n(no of rows or columns)consider

-1

all other elements are zero but my pgm would proclaim it to be a identity matrix sorry for my blip,\...

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