|
|
|
|
|
| Author |
Message |
![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 Nov 2007 00:27:09 IST
|
|
|
pls solve
|
B.Tech CSE, ISMU |
|
|
|
9 Nov 2007 00:30:23 IST
|
|
|
ans given is (B)
|
B.Tech CSE, ISMU |
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
9 Nov 2007 00:38:57 IST
|
|
|
Let us find d2x/dy2.
d2x/dy2 = d(dx/dy) / dy
Now divide numerator and denominator by dx.
Numerator becomes d(dx/dy) / dx = d(1/y')/dx = {-1/(y')2}.dy'/dx = -y''/(y')2
Denominator becomes dy/dx = y'
so, d2x/dy2 = {-y''/(y')2} / y'
y'' + (y')3d2x/dy2 = 0
d2y/dx2 + (dy/dx)3.d2x/dy2 = 0
|
Bipin Kumar Dubey
Chemical Dept.
IIT Kharagpur
|
this reply: 5 points
(with 1
in 1 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
|
|
|
|
|
|
|
Moderation Team
![[Up]](/templates/default/images/icon_up.gif "[Up]"){kind=icon}
![[Thumb - Picture2.png]](/upload/2007/11/9/7480cc04d1558745604550b6d5203b8c_6351.png_thumb)
1
